The sum ∑ n = 1^∞tan^-1 (4n/n^4-2n^2+2) is equal to
How can tangent approach negative infinity at +Pi/2 (for example) and how can it approach positive infinity at negative pi/2? I understand why it's negative infinity at negative pi/2 ( sinx=-1, cosx=0,
SOLVED:Use the power series for tan ^-1 x to prove the following expression for πas the sum of an infinite series: π=2 √(3) ∑n=0^∞ ((-1)^n)/((2 n+1) 3^n)
Solved] why is arctan of infinity gives pi/2? you are welcome to use the... | Course Hero
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Solved] why is arctan of infinity gives pi/2? you are welcome to use the... | Course Hero
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If tan^-1 (a/x) + tan^-1 (b/x) = pi/2 , then x is equal to :